Maharashtra State Board · HSC Commerce · Class 12 (Std XII)
Class 12 Maths and Statistics Part 1 Chapter 4: Applications of Derivatives
Short notes, key concepts, quick revision and practice MCQs with answers
Derivatives describe slopes and rates. The chapter finds equations of tangents and normals, tests whether functions are increasing or decreasing, locates maxima and minima, and applies derivatives to economics: demand, supply, cost, revenue, profit, elasticity and the propensities to consume and save.
Key concepts: Applications of Derivatives
- Tangent and normal
- The slope of the tangent to y = f(x) at P(a, b) is f′(a). Tangent: y − b = f′(a)(x − a). Normal: y − b = (−1/f′(a))(x − a), f′(a) ≠ 0.
- Increasing and decreasing functions
- f is increasing at c if f′(c) > 0 and decreasing at c if f′(c) < 0.
- Maxima and minima
- If f′(c) = 0 and f″(c) < 0, f has a local maximum at c; if f′(c) = 0 and f″(c) > 0, a local minimum. Points where f′(x) = 0 are stationary points.
- Cost and revenue
- Total cost C = f(x); average cost = C/x; marginal cost = dC/dx. Revenue R = P × D; average revenue RA = R/D = P; marginal revenue Rm = dR/dD.
- Profit
- Profit π = R − C. It is maximum where dπ/dx = 0 and d²π/dx² < 0.
- Elasticity of demand
- η = −(P/D)(dD/dP). Demand is elastic if η > 1, unitary if η = 1 and inelastic if η < 1.
- Revenue and elasticity
- Rm = P(1 − 1/η) = RA(1 − 1/η). When η = 1, Rm = 0.
- Consumption and saving
- For income x = Ec + S: MPC = dEc/dx, MPS = dS/dx, APC = Ec/x, APS = S/x. MPC + MPS = 1 and APC + APS = 1.
Quick revision: important points
- Slope of the normal × slope of the tangent = −1.
- Marginal demand = dD/dP and marginal supply = dS/dP.
- For maximum revenue, dR/dx = 0 and d²R/dx² < 0.
- A stationary point is where the tangent is parallel to the X-axis.
- If MPC = 0.8, then MPS = 0.2.
Practice MCQs with answers
The slope of the tangent to y = x² + 4x + 1 at x = −1 is:
- 0
- 2
- 4
- −2
Show answer
Answer: B. 2
dy/dx = 2x + 4 = 2 at x = −1.The equation of the tangent to y = f(x) at P(a, b) is:
- y − b = f(a)(x − a)
- y − b = f′(a)(x − a)
- y − a = f′(b)(x − b)
- x − a = f′(a)(y − b)
Show answer
Answer: B. y − b = f′(a)(x − a)
Slope-point form with slope f′(a).The slope of the normal to y = f(x) at x = a is:
- f′(a)
- −f′(a)
- −1/f′(a)
- 1/f′(a)
Show answer
Answer: C. −1/f′(a)
The normal is perpendicular to the tangent.A function f is increasing at x = c if:
- f′(c) < 0
- f′(c) > 0
- f′(c) = 0
- f(c) > 0
Show answer
Answer: B. f′(c) > 0
A positive derivative means rising.f(x) = x³ + 3x is:
- Increasing for all real x
- Decreasing for all real x
- Increasing only for x > 0
- Constant
Show answer
Answer: A. Increasing for all real x
f′(x) = 3x² + 3 > 0 always.
All Class 12 Maths and Statistics chapters
- Part 1 Chapter 1: Mathematical Logic
- Part 1 Chapter 2: Matrices
- Part 1 Chapter 3: Differentiation
- Part 1 Chapter 4: Applications of Derivatives
- Part 1 Chapter 5: Integration
- Part 1 Chapter 6: Definite Integration
- Part 1 Chapter 7: Application of Definite Integration
- Part 1 Chapter 8: Differential Equation and Applications
- Part 2 Chapter 1: Commission, Brokerage and Discount
- Part 2 Chapter 2: Insurance and Annuity
- Part 2 Chapter 3: Linear Regression
- Part 2 Chapter 4: Time Series
- Part 2 Chapter 5: Index Numbers
- Part 2 Chapter 6: Linear Programming
- Part 2 Chapter 7: Assignment Problem and Sequencing
- Part 2 Chapter 8: Probability Distributions